Blockaway Proxy

Open the "Start" menu and type "Browser Properties" in the search box. Then, go to the "Connection" tab, click on "Network settings" and disable the use of the proxy server. Reboot Windows and check if your Internet connection works. If the problem persists, open the "Advanced" tab in the "Browser Properties" window and check the box next to "Delete personal settings", click "Reset" and restart your computer.

In Windows 10 you need to go to "Settings", go to "Network and Internet", open the tab "Proxy" and make the necessary settings for the connection (under "Manual", the item should also be made active).

When performing web scraping with authorization in Python, you typically need to simulate the login process of a user by sending the necessary authentication data (such as username and password) to the website. The exact steps depend on the authentication method used by the website, and there are several common approaches

Basic Authentication (using requests library)

If the website uses HTTP Basic Authentication, you can include the authentication credentials in the request headers using the requests library.

import requests

url = 'https://example.com/data'
username = 'your_username'
password = 'your_password'

response = requests.get(url, auth=(username, password))

if response.status_code == 200:
    # Successfully authenticated, you can now parse the content
    print(response.text)
else:
    print(f"Failed to authenticate. Status code: {response.status_code}")

Form-Based Authentication

For websites that use form-based authentication (login form), you need to send a POST request with the appropriate form data.

import requests

login_url = 'https://example.com/login'
data = {
    'username': 'your_username',
    'password': 'your_password',
}

# Use a session to persist the authentication across requests
with requests.Session() as session:
    response = session.post(login_url, data=data)

    if response.status_code == 200:
        # Authentication successful, continue with subsequent requests
        data_url = 'https://example.com/data'
        data_response = session.get(data_url)
        print(data_response.text)
    else:
        print(f"Failed to authenticate. Status code: {response.status_code}")

OAuth Authentication

For websites using OAuth, you might need to use an OAuth library like requests_oauthlib or oauthlib to handle the OAuth flow.

Handling Cookies

Sometimes, authentication is maintained using cookies. In such cases, you need to handle cookies in your requests.

import requests

login_url = 'https://example.com/login'
data = {
    'username': 'your_username',
    'password': 'your_password',
}

# Use a session to persist the authentication across requests
with requests.Session() as session:
    login_response = session.post(login_url, data=data)

    if login_response.status_code == 200:
        # Authentication successful, continue with subsequent requests
        data_url = 'https://example.com/data'
        data_response = session.get(data_url)
        print(data_response.text)
    else:
        print(f"Failed to authenticate. Status code: {login_response.status_code}")

Bypassing CAPTCHA (Completely Automated Public Turing test to tell Computers and Humans Apart) is generally considered unethical and against the terms of service of most websites. CAPTCHAs are designed to ensure that interactions with a website are performed by humans rather than automated scripts. Attempting to bypass CAPTCHA measures without explicit permission is likely to violate the website's terms of service and may have legal consequences.

If you are facing challenges with CAPTCHAs while using Selenium, consider the following alternatives:

1. Use CAPTCHA Solving Services:

   • Some third-party services offer CAPTCHA solving solutions. These services may use human workers to solve CAPTCHAs for you. However, keep in mind that using such services may still violate the terms of service of the website.

2. Contact the Website Owner:

   • If you are legitimately using Selenium for testing purposes or any other sanctioned activity, consider reaching out to the website owner or administrator. They may provide you with a way to bypass CAPTCHAs for testing purposes.

3. Use Headless Browsing:

   • Some websites may implement CAPTCHAs only for users interacting with the website in a visible browser window. Running Selenium in headless mode (without a visible browser) may reduce the likelihood of encountering CAPTCHAs.

4. Automate Only What's Necessary:

   • Avoid unnecessary interactions with the website and automate only what is essential. Excessive and rapid interactions may trigger CAPTCHAs.

5. Consider Alternatives:

   • Explore alternatives to web scraping if CAPTCHAs are a significant obstacle. Some websites provide APIs or other methods for accessing data without the need for traditional web scraping.

Always respect the terms of service of the websites you are interacting with and seek permission if you encounter obstacles like CAPTCHAs. Attempting to bypass security measures without authorization is not only unethical but may also lead to legal consequences.

In Selenium, you can find out the URL of a newly opened window by switching to that window and retrieving its URL. Here's a step-by-step guide in Python:

1. Switch to the New Window

After opening a new window, you need to switch the focus of the WebDriver to that window.

from selenium import webdriver

driver = webdriver.Chrome()
driver.get("https://example.com")

# Open a new window (e.g., by clicking a link)
new_window_link = driver.find_element_by_link_text("Open New Window")
new_window_link.click()

# Switch to the new window
new_window_handle = driver.window_handles[-1]
driver.switch_to.window(new_window_handle)

In this example, replace "Open New Window" with the actual link text or locator that opens the new window.

2. Retrieve the URL of the New Window

Once you have switched to the new window, you can retrieve its URL using current_url.

new_window_url = driver.current_url
print("URL of the new window:", new_window_url)

This will print the URL of the new window. You can then store it in a variable or use it as needed in your script.

3. Switch Back to the Original Window (Optional)

If you need to switch back to the original window after retrieving the URL from the new window, you can do so using a similar process.

original_window_handle = driver.window_handles[0]
driver.switch_to.window(original_window_handle)

Replace 0 with the index of the original window's handle in the window_handles list.

Here's the complete example:

from selenium import webdriver

driver = webdriver.Chrome()
driver.get("https://example.com")

# Open a new window (replace with the actual link or action)
new_window_link = driver.find_element_by_link_text("Open New Window")
new_window_link.click()

# Switch to the new window
new_window_handle = driver.window_handles[-1]
driver.switch_to.window(new_window_handle)

# Retrieve the URL of the new window
new_window_url = driver.current_url
print("URL of the new window:", new_window_url)

# Switch back to the original window (optional)
original_window_handle = driver.window_handles[0]
driver.switch_to.window(original_window_handle)

# Continue with your script...

# Close the browser when done
driver.quit()

Make sure to adjust the code based on the actual actions and elements in your application that trigger the opening of a new window.