IP | Country | PORT | ADDED |
---|---|---|---|
194.87.93.21 | ru | 1080 | 7 minutes ago |
50.223.246.236 | us | 80 | 7 minutes ago |
50.175.212.76 | us | 80 | 7 minutes ago |
50.168.61.234 | us | 80 | 7 minutes ago |
50.169.222.242 | us | 80 | 7 minutes ago |
50.145.138.146 | us | 80 | 7 minutes ago |
103.216.50.11 | kh | 8080 | 7 minutes ago |
87.229.198.198 | ru | 3629 | 7 minutes ago |
203.99.240.179 | jp | 80 | 7 minutes ago |
194.158.203.14 | by | 80 | 7 minutes ago |
50.237.207.186 | us | 80 | 7 minutes ago |
140.245.115.151 | sg | 6080 | 7 minutes ago |
50.218.208.15 | us | 80 | 7 minutes ago |
70.166.167.55 | us | 57745 | 7 minutes ago |
212.69.125.33 | ru | 80 | 7 minutes ago |
50.171.122.24 | us | 80 | 7 minutes ago |
50.175.123.232 | us | 80 | 7 minutes ago |
50.169.222.244 | us | 80 | 7 minutes ago |
203.99.240.182 | jp | 80 | 7 minutes ago |
158.255.77.169 | ae | 80 | 7 minutes ago |
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It depends on the purpose for which you plan to work with proxies at all. Personally, one is enough for myself. But if you plan to do massive parsing, it may not be enough to have 100 pieces.
Scraping data from a community wall on VK (Vkontakte) using the VK API requires authentication and making requests to the API endpoints. VK provides an official API that you can use to access various data, including posts from community walls.
Here's a general guide on how to scrape posts from a community wall using the VK API:
Create a VK App:
Authentication:
Make API Requests:
wall.get
.Here's an example using Python and the requests
library:
import requests
# Replace with your VK app details and access token
app_id = 'your_app_id'
secure_key = 'your_secure_key'
access_token = 'your_access_token'
# Replace with the community ID or screen name
community_id = 'your_community_id_or_screen_name'
# API endpoint for getting wall posts
api_url = f'https://api.vk.com/method/wall.get?owner_id=-{community_id}&count=10&access_token={access_token}&v=5.131'
# Make the API request
response = requests.get(api_url)
data = response.json()
# Extract and print the posts
if 'response' in data and 'items' in data['response']:
posts = data['response']['items']
for post in posts:
print(post['text'])
else:
print('Error fetching wall posts')
Note: Make sure to handle errors and check the VK API documentation for more details on available parameters and responses.
If you're parsing XML in Golang and the result is not being saved in the structure as expected, there might be issues with your XML parsing code. Below is a simple example demonstrating how to parse XML and save the result in a structure using the encoding/xml package in Golang.
Assuming you have the following XML structure:
John Doe
30
And you want to parse it into the following Go structure:
package main
import (
"encoding/xml"
"fmt"
)
type User struct {
Name string `xml:"name"`
Age int `xml:"age"`
}
func main() {
xmlData := `John Doe 30 `
var user User
// Unmarshal XML into the User structure
err := xml.Unmarshal([]byte(xmlData), &user)
if err != nil {
fmt.Println("Error:", err)
return
}
// Print the result
fmt.Printf("Name: %s\nAge: %d\n", user.Name, user.Age)
}
In this example:
The User struct tags (e.g., xml:"name") indicate the mapping between the XML elements and the fields in the structure.
xml.Unmarshal is used to parse the XML data and populate the User structure.
Ensure that your XML data and struct tags match correctly. If the XML structure or tags are different, you might encounter issues with parsing.
If you continue to face problems, please provide more details or your specific code for further assistance.
To upload files using Selenium, you can follow these general steps:
Locate the file input element: Use Selenium's methods like find_element_by_id(), find_element_by_name(), or find_element_by_xpath() to locate the file input element on the webpage.
Send keys to the file input element: Use the send_keys() method to send the file path to the file input element. This will upload the file.
Here's an example using Python:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
# Replace 'your_url' with the URL of the webpage you want to open
driver = webdriver.Chrome()
driver.get('your_url')
# Replace 'file_input_id' with the ID of the file input element on the webpage
file_input = driver.find_element(By.ID, 'file_input_id')
# Replace 'path/to/your/file' with the path to the file you want to upload
file_path = 'path/to/your/file'
file_input.send_keys(file_path)
# Rest of your code
driver.quit()
Keep in mind that the specific method to locate the file input element and the file input element's ID or name may vary depending on the webpage you're working with.
Additionally, some websites may have specific requirements or restrictions for uploading files. In such cases, you may need to use JavaScript or other methods to bypass these restrictions. If you encounter any issues or need further assistance, please provide more information about the webpage and the specific error message or problem you're facing.
To add a proxy in ZennoPoster, follow these steps:
1. Open ZennoPoster and go to the "Settings" menu.
2. Select "Network settings" or "Proxy settings" depending on the version you are using.
3. Click on the "Add" button to create a new proxy profile.
4. Enter the proxy server address, port, and select the protocol (HTTP or HTTPS) from the drop-down menu.
5. If your proxy requires authentication, enter the username and password in the respective fields.
6. Click "Save" to add the proxy profile.
7. To use the proxy, select it from the list of available proxies in the "Proxies" section of your task settings.
What else…