IP | Country | PORT | ADDED |
---|---|---|---|
50.217.226.41 | us | 80 | 5 minutes ago |
209.97.150.167 | us | 3128 | 5 minutes ago |
50.174.7.162 | us | 80 | 5 minutes ago |
50.169.37.50 | us | 80 | 5 minutes ago |
190.108.84.168 | pe | 4145 | 5 minutes ago |
50.174.7.159 | us | 80 | 5 minutes ago |
72.10.160.91 | ca | 29605 | 5 minutes ago |
50.171.122.27 | us | 80 | 5 minutes ago |
218.252.231.17 | hk | 80 | 5 minutes ago |
50.220.168.134 | us | 80 | 5 minutes ago |
50.223.246.238 | us | 80 | 5 minutes ago |
185.132.242.212 | ru | 8083 | 5 minutes ago |
159.203.61.169 | ca | 8080 | 5 minutes ago |
50.223.246.239 | us | 80 | 5 minutes ago |
47.243.114.192 | hk | 8180 | 5 minutes ago |
50.169.222.243 | us | 80 | 5 minutes ago |
72.10.160.174 | ca | 1871 | 5 minutes ago |
50.174.7.152 | us | 80 | 5 minutes ago |
50.174.7.157 | us | 80 | 5 minutes ago |
50.174.7.154 | us | 80 | 5 minutes ago |
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If your proxy gives you a 504 error, it means the server failed to complete the request within the time period you specified. Refreshing the page may help. Another option is to switch to another browser. You can also use the incognito mode, pre-clearing the browser cache. Pay attention to plug-ins that can also cause this error.
The provider, when the user uses a VPN, "sees" only the encrypted traffic, as well as the address of the remote server to which the request is sent. But it is impossible to determine which site the user is visiting and what data is being sent.
In Selenium, you can find out the URL of a newly opened window by switching to that window and retrieving its URL. Here's a step-by-step guide in Python:
1. Switch to the New Window
After opening a new window, you need to switch the focus of the WebDriver to that window.
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://example.com")
# Open a new window (e.g., by clicking a link)
new_window_link = driver.find_element_by_link_text("Open New Window")
new_window_link.click()
# Switch to the new window
new_window_handle = driver.window_handles[-1]
driver.switch_to.window(new_window_handle)
In this example, replace "Open New Window" with the actual link text or locator that opens the new window.
2. Retrieve the URL of the New Window
Once you have switched to the new window, you can retrieve its URL using current_url.
new_window_url = driver.current_url
print("URL of the new window:", new_window_url)
This will print the URL of the new window. You can then store it in a variable or use it as needed in your script.
3. Switch Back to the Original Window (Optional)
If you need to switch back to the original window after retrieving the URL from the new window, you can do so using a similar process.
original_window_handle = driver.window_handles[0]
driver.switch_to.window(original_window_handle)
Replace 0 with the index of the original window's handle in the window_handles list.
Here's the complete example:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get("https://example.com")
# Open a new window (replace with the actual link or action)
new_window_link = driver.find_element_by_link_text("Open New Window")
new_window_link.click()
# Switch to the new window
new_window_handle = driver.window_handles[-1]
driver.switch_to.window(new_window_handle)
# Retrieve the URL of the new window
new_window_url = driver.current_url
print("URL of the new window:", new_window_url)
# Switch back to the original window (optional)
original_window_handle = driver.window_handles[0]
driver.switch_to.window(original_window_handle)
# Continue with your script...
# Close the browser when done
driver.quit()
Make sure to adjust the code based on the actual actions and elements in your application that trigger the opening of a new window.
To log into your Google account using Selenium, you will need to follow these steps:
1. Install Selenium WebDriver for your preferred browser (e.g., Chrome, Firefox, Edge).
2. Import the necessary modules in your script.
3. Create a WebDriver instance for the browser.
4. Navigate to the Google login page (https://accounts.google.com/).
5. Locate the email and password input fields and the login button.
6. Enter your email and password into the input fields.
7. Click the login button.
Here's an example Python script using Selenium with Chrome WebDriver:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
# Set up the Chrome WebDriver
driver = webdriver.Chrome()
# Navigate to the Google login page
driver.get("https://accounts.google.com/")
# Explicit wait for the email input field to be present
wait = WebDriverWait(driver, 10)
email_input = wait.until(EC.presence_of_element_located((By.NAME, "identifier")))
# Enter your email address into the email input field
email_input.send_keys("[email protected]")
email_input.send_keys(Keys.RETURN)
# Explicit wait for the password input field to be present
password_input = wait.until(EC.presence_of_element_located((By.NAME, "password")))
# Enter your password into the password input field
password_input.send_keys("your_password")
password_input.send_keys(Keys.RETURN)
# Your Google account should now be logged in
Replace [email protected] and your_password with your actual Google account email and password. Note that storing passwords in plaintext within your script is not secure. Consider using environment variables or other secure methods to store sensitive information.
Keep in mind that Google may have CAPTCHA or other security measures in place to prevent automated logins. If you encounter such measures, you may need to use additional techniques or services to bypass them.
Proxies in Instagram are most often used for two purposes. The first is to bypass access blocking. The second is to avoid being banned when working with several accounts at once. The latter, as a rule, is used when arbitrating traffic, when launching massive advertising campaigns, which allows you not to worry about possibly getting a permanent ban.
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