IP | Country | PORT | ADDED |
---|---|---|---|
41.230.216.70 | tn | 80 | 40 minutes ago |
50.168.72.114 | us | 80 | 40 minutes ago |
50.207.199.84 | us | 80 | 40 minutes ago |
50.172.75.123 | us | 80 | 40 minutes ago |
50.168.72.122 | us | 80 | 40 minutes ago |
194.219.134.234 | gr | 80 | 40 minutes ago |
50.172.75.126 | us | 80 | 40 minutes ago |
50.223.246.238 | us | 80 | 40 minutes ago |
178.177.54.157 | ru | 8080 | 40 minutes ago |
190.58.248.86 | tt | 80 | 40 minutes ago |
185.132.242.212 | ru | 8083 | 40 minutes ago |
62.99.138.162 | at | 80 | 40 minutes ago |
50.145.138.156 | us | 80 | 40 minutes ago |
202.85.222.115 | cn | 18081 | 40 minutes ago |
120.132.52.172 | cn | 8888 | 40 minutes ago |
47.243.114.192 | hk | 8180 | 40 minutes ago |
218.252.231.17 | hk | 80 | 40 minutes ago |
50.175.123.233 | us | 80 | 40 minutes ago |
50.175.123.238 | us | 80 | 40 minutes ago |
50.171.122.27 | us | 80 | 40 minutes ago |
Simple tool for complete proxy management - purchase, renewal, IP list update, binding change, upload lists. With easy integration into all popular programming languages, PapaProxy API is a great choice for developers looking to optimize their systems.
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If you're working with Spring Boot in Java and need to parse JSON with multiple attachments, you might be dealing with a scenario involving HTTP requests with JSON payload and file attachments. In this case, you can use @RequestPart in your controller method to handle JSON and multipart requests.
Here's a basic example
Create a DTO (Data Transfer Object) class:
public class RequestDto {
private String jsonData;
private MultipartFile file1;
private MultipartFile file2;
// getters and setters
}
Create a controller with a method to handle the request:
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.PostMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestPart;
import org.springframework.web.bind.annotation.RestController;
import org.springframework.web.multipart.MultipartFile;
@RestController
@RequestMapping("/api")
public class ApiController {
@PostMapping("/processRequest")
public ResponseEntity processRequest(@RequestPart("requestDto") RequestDto requestDto,
@RequestPart("file1") MultipartFile file1,
@RequestPart("file2") MultipartFile file2) {
// Process JSON data in requestDto and handle file attachments
// ...
return ResponseEntity.ok("Request processed successfully");
}
}
Using tools like Postman or curl, you can send a multipart request. Here's an example using Postman:
http://localhost:8080/api/processRequest
.requestDto
, Value: {"jsonData": "your_json_data"}
file1
, Value: select a filefile2
, Value: select another fileMake sure you have the appropriate dependencies in your project for handling multipart requests. If you're using Maven, you can include the following dependency in your pom.xml
:
org.springframework.boot
spring-boot-starter-web
Adjust the example based on your specific use case and the structure of your JSON data. The key point is to use @RequestPart to handle both JSON and file attachments in the same request.
To scrape Binance courses data in Python, you can use web scraping libraries such as BeautifulSoup and requests. Here's an example using BeautifulSoup to scrape Binance courses
Install required libraries:
pip install beautifulsoup4 requests
Write the scraping code:
import requests
from bs4 import BeautifulSoup
def scrape_binance_courses():
url = 'https://www.binance.com/en/academy/courses'
# Send a GET request to the URL
response = requests.get(url)
# Check if the request was successful (status code 200)
if response.status_code == 200:
soup = BeautifulSoup(response.text, 'html.parser')
# Find the container containing course information
course_container = soup.find('div', {'class': 'css-7sfsgn'})
if course_container:
# Extract course details
courses = course_container.find_all('div', {'class': 'css-1jiwjuo'})
for course in courses:
course_title = course.find('div', {'class': 'css-1mg41yd'}).text
course_description = course.find('div', {'class': 'css-1q62c8m'}).text
print(f"Title: {course_title}\nDescription: {course_description}\n")
else:
print("Course container not found.")
else:
print(f"Failed to retrieve the webpage. Status code: {response.status_code}")
# Run the scraping function
scrape_binance_courses()
This example sends a GET request to the Binance Academy courses page, parses the HTML content using BeautifulSoup, and extracts course details such as title and description.
Run the code:
python your_script_name.py
In Selenium, you can load a cookie using the add_cookie() method of the WebDriver object. Here's an example of how to do it:
from selenium import webdriver
# Initialize the WebDriver (e.g., Chrome)
driver = webdriver.Chrome()
# Define the cookie you want to load
cookie = {
"name": "username",
"value": "testuser",
"domain": ".example.com",
"path": "/",
"secure": True,
}
# Add the cookie to the WebDriver
driver.add_cookie(cookie)
# Navigate to the page you want to load with the cookie
driver.get("http://example.com")
In this example, we're using the Chrome WebDriver to add a cookie named "username" with the value "testuser" to the domain ".example.com". The add_cookie() method accepts a dictionary representing the cookie, which includes the name, value, domain, path, secure flag, and other attributes.
After adding the cookie, you can navigate to the desired page using the get() method. The WebDriver will now send the cookie along with each request made to the server.
To upload files using Selenium, you can follow these general steps:
Locate the file input element: Use Selenium's methods like find_element_by_id(), find_element_by_name(), or find_element_by_xpath() to locate the file input element on the webpage.
Send keys to the file input element: Use the send_keys() method to send the file path to the file input element. This will upload the file.
Here's an example using Python:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
# Replace 'your_url' with the URL of the webpage you want to open
driver = webdriver.Chrome()
driver.get('your_url')
# Replace 'file_input_id' with the ID of the file input element on the webpage
file_input = driver.find_element(By.ID, 'file_input_id')
# Replace 'path/to/your/file' with the path to the file you want to upload
file_path = 'path/to/your/file'
file_input.send_keys(file_path)
# Rest of your code
driver.quit()
Keep in mind that the specific method to locate the file input element and the file input element's ID or name may vary depending on the webpage you're working with.
Additionally, some websites may have specific requirements or restrictions for uploading files. In such cases, you may need to use JavaScript or other methods to bypass these restrictions. If you encounter any issues or need further assistance, please provide more information about the webpage and the specific error message or problem you're facing.
This depends directly on how the proxy server works. Some of them do not require any authorization at all, others require username and password for access, and others require you to view ads and so on. Which option will be used depends directly on the service that provides access to the proxy server.
What else…